Can the halting problem be NP-complete?

There are decision problems that are NP-hard but not NP-complete such as the halting problem. That is the problem which asks “given a program and its input, will it run forever?” That is a yes/no question and so is a decision problem. There are also NP-hard problems that are neither NP-complete nor Undecidable.

Which problems can be NP-complete?

NP-complete problem, any of a class of computational problems for which no efficient solution algorithm has been found. Many significant computer-science problems belong to this class—e.g., the traveling salesman problem, satisfiability problems, and graph-covering problems.

Is halt in NP-hard?

We showed that HALT is NP-hard, so every problem in NP reduces to it. Informally, this means that HALT is at least as hard as every problem in NP. This should be expected, since HALT is undecidable (and thus very, very hard).

Which problem is not NP-complete?

Which of the following problems is not NP complete? Explanation: Hamiltonian circuit, bin packing, partition problems are NP complete problems. Halting problem is an undecidable problem.

Is chess a NP?

For two-player games, one encounters a similar phenomenon at a higher level of complexity. For this reason games like chess cannot themselves be NP-complete, as they only have a finite (albeit unthinkably large) number of possible positions.

Is Halting Problem complete?

The halting problem is a decision problem about properties of computer programs on a fixed Turing-complete model of computation, i.e., all programs that can be written in some given programming language that is general enough to be equivalent to a Turing machine.

Is Othello NP-complete?

Iwata and T. Kasai, The Othello game on an n*n board is PSPACE-complete, Theor.

How many steps is needed to justify if any decision problem is NP-complete?

Q.	How many steps are required to prove that a decision problem is NP complete?
C.	3
D.	4
Answer» b. 2
Explanation: first, the problem should be np. next, it should be proved that every problem in np is reducible to the problem in question in polynomial time.

What is the halting problem in NP?

The halting problem is the classic NP-hard problem. This is the problem that given a program P and input I, will it halt? This is a decision problem but it is not in NP. It is clear that any NP-complete problem can be reduced to this one.

What is the classic NP-hard problem?

– Stack Overflow In this answer to a question about the definitions of NP, NP-hard, and NP-complete, Jason makes the claim that The halting problem is the classic NP-hard problem. This is the problem that given a

How do you prove that a problem is NP-complete?

From the definition of NP-complete, it appears impossible to prove that a problem L is NP-Complete. By definition, it requires us to that show every problem in NP is polynomial time reducible to L. Fortunately, there is an alternate way to prove it.

Is NP-completeness good or bad news?

So far we’ve seen a lot of good news: such-and-such a problem can be solved quickly (in close to linear time, or at least a time that is some small polynomial function of the input size). NP-completeness is a form of bad news: evidence that many important problems can’t be solved quickly.